SOLUTION OF SWING EQUATION

Jun 17 • General • 9156 Views • 3 Comments on SOLUTION OF SWING EQUATION

SOLUTION OF SWING EQUATION USING STEP BY STEP METHOD

The step  by step method used for hand calculation is better and simpler than the methods used for the computers in this method of the hand calculation the angular position of the rotor is changed during the short interval of time and is computed using some assumptions  and these assumptions are-:

1. Accelerating power Pa which is doesnot change at the initial interval, which is the proceeding interval from the middle to middle of that interval.
2. Throughout any interval angular velocity is constant at a value computed from the middle of the interval

But the above assumptions are not accurate because delta is changing continuously  and both Pa and w are functions of delta. As the time interval is decreased the computed swing curve tends to accuracy.

 SWING EQUATION SOLUTION USING MODIFIED EULER METHOD

Before we discuss the application of Euler’s method for solving the swing equations we should  know the basic Euler’s method of numerical integration so the general form of the equation is –

Y’ = f (x,y)                       Y(xo)= yo

Where  x is  independent and y is dependent quantities  whereas  xo  and yo

Is the initial value of x and y respective here  the independent axis  that is the x-axis is divided to intervals of length ‘h’ so that the discrete points on the independent axis will be xo, xo + h, xo + 2h, etc.

Our task  is to calculate the values y1, y2, corresponding to the x co-ordinates after  these values are calculated  the curve representing the solution of differential equation given in equation  can be plotted.

In this method the  y1, y2,  values are calculated in two steps predictor and corrector and then it is determined.

SWING EQUATION SOLUTION BY RANGE KUTTA METHOD

In this method we consider two equation –

X1=f(x1,x2)

X2=f(x1,x2)

And set the count k=0 and assume solution in terms of x1^0 and x2^0

QUESTIONS AND ANSWERS

1. What are the advantages of the per unit system?

Ans-    It yields important information about the relative magnitudes, identifies the error data.

1. Why the transmission stability is lower that the steady state stability?

Ans- this is because the maximum power flow in transient stability is less that the maximum power flow in steady state stability.

GATE Syllabus-

1. Gate Syllabus for Mathematics 2014

2. Gate Syllabus for Electronics and Communication 2014

IES Syllabus-

1. IES Syllabus for Electronics and Telecommunication

2. IES Syllabus for General Ability

Solution by euler methodsolution by step by step methodSOLUTION OF SWING EQUATIONSOLUTION OF SWING EQUATION BY RANGE KUTTA METHOD

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