BPUT Sample Paper for Modern Manufacturing Process
BPUT Sample Paper for Modern Manufacturing Process
TIME=3 HOURS
FULL MARK=70
NO1 ALL QUESTIONS ARE COMPULSORY.
ANY FIVE FROM THE REST
ANSWER THE FOLLOWING QUESTIONS.
1(a) what are various factors that you will keep in mind, while selecting pattern material?
Ans : (i) number of castings to be made.
ii)method of moulding to be used i.e hand or machine.
iii) type of casting method to be used.
iv) degree of accuracy in dimension and the quality of surface finish required in the casting.
v) design of casting
(b) what is parting sand ?
Ans: This term denotes that sand which is sprinkled on the pattern and the parting surfaces of the mould so that the sand mass of one flask does not stick to that of the other or the pattern . The burnt sand and dry silica sand are used for this purpose
(c) what are the main constituents of moulding sand ?
Ans: The main constituents are :
i) silica sand, ii) binder, iii) additives, iv) water
(d) Differentiate between normal strain or natural strain ?
Ans: Normal strain is the change in length with respect to original length where as natural strain is the change on length with respect to constant a news length.
(e) why chills are used in moulds?
Ans: chills are used in moulds for achieving directional solidification
(f) Expain how can we find bearing number or bearing size?
Ans. We can find bearing number or bearing size through a commercial catalog for some companies like SKF or by reading the size on the cylinder block
(g) What “psi” represent?
Ans. psi is an abbreviation for pounds force per square inch and can be commonly seen on pressure gauges as unit.
(h) Define four stroke engine?
Ans. In four stroke engine there are two valves i.e. one is inlet and another is exhaust. The stroke is done one by one in sequence as suction, compression, power and exhaust and for every four stroke there is one power.
(I). Differentiate between a pipe and tube?
Ans. Pipe is usually denoted by OD x gauge. Pipe is used to transfer liquid or gas. Pipe is flexible. Pipe is disignated with its Inner dia.
Tube is denoted by ID which is NB x sch.Tube is used to transfer Heat. Tube is Rigid and is designated with Outer Diameter.
(j) What will be the consequence when water flowing through pipe is suddenly cut?
Ans. When water flowing through a pipe is suddenly stopped, a pressure wave eqiuvalent to sound will get created and will move to and fro. It causes damage to pipe by suddenly hitting the pipe wall which is known as water hammering
2) Do the CGMPs require a firm to retain the equipment status identification labels with the batch record or other file? Assuming each major piece of equipment has a unique “Cleaning and Use Log” that is adequately retained, is it acceptable to discard these ‘quick reference’ equipment labels?
Ans: The CGMP regulations for finished pharmaceuticals require the retention of cleaning and use logs for non-dedicated equipment, but no similar requirement exists for retaining what are intended to be “quick reference” or temporary status labels. Examples of these kinds of status labels include “mixing lot ###”; “clean, ready for use as of d/M/y”; “not clean.” We see no value in the retention of such labels in addition to the required equipment log or batch record documentation. The labels serve a valuable, temporary purpose of positively identifying the current status of equipment and the material under process. Any status label should be correct, legible, readily visible, and associated with the correct piece of equipment. The information on the temporary status label should correspond with the information recorded in the equipment cleaning and use log, or the previous batch record for non-dedicated equipment.
Labels are merely one way to display temporary status information about a piece of equipment. It is considered acceptable practice to display temporary equipment status information on dry-erase boards or chalkboards. And it would be appropriate for an FDA investigator to verify that the information on a temporary status label is consistent with the log.
3) Can Leptospira species penetrate sterilizing-grade filters? If so, what should manufacturers keep in mind in their ongoing lifecycle risk management efforts to assure microbial control?
- penetrate sterilizing-grade membrane filters
- be present in the manufacturing site environment
- impact in-process production (e.g., production yields, impurity levels, process performance)
- go undetected due to the limitations of current compendial bioburden tests in detecting this microbial genus
- Review of available published articles from the scientific literature and technical reports by related industry organizations that may provide further understanding on how to mitigate this contamination hazard.
- Use of molecular or nonconventional microbial monitoring methods at appropriate intervals to detect microbial flora that may exist in processing steps or in the immediate environment, but are not readily detected by current routine methods. Such expanded testing should be used to modify the strategy (e.g., timing, frequency, types of tests) of detection and control in the event of newly-identified risk posed by the viable, but not easily cultured, microorganism.
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4.Calculate the diameter of punch and press capacity for 50mm diameter disc to be punched out from a carbon steel sheet 1 mm thick Also Calculate the punch size and dia size (ulternate shear stress S=42 kg f/mm2)
Soln: Data given
D =50 mm , t= 1mm
Shear length = πd =157.05
Shear area =πDt=157.05 mm2
Press capacity in tomnage required
=πDt×S /1000=157.05×42/1000=6596 ton
Empenical formula for Clearance
=0.00032×t×sqrt.ԏmm
ԏ=mat 1. Shear stress in Mpa 42 kg f/mm2
t=sheet thickness mm
=0.0032×t×sqrt.412=0.064mm/side
For blanking component size=Die size clearance will be on the punch
Die size=50 mm
Punch size=50-2×(clearance)
50-2×(0.0064)=50-90.13=49.87 mm
5.Spot welding of two 1 mm thickness sheet of steel is carried successfully by pasing a certain amount
Of current from 0.1 second through the electrodes.The resultant weld nugget formed is 5 mm india 1.5 mm thick calculate the amount of current passing through electrode?
If Psteel=8000kg/m3
Content heat of fusion=hf=1400 kj/kg
Resistance of welding operation=200 micro ohm=200×10-6 ohm
Sol:As per the data given in the question
Volume of nugget is=(π/4×d2×t)=π/4×52×15 mm3
=29.4375×10-9 m3
Amount of heat required to melting
=hf×p×v
=1400kj/k×8000 kg/m3×29.4375×10-9=329.7 joule
But in spot welding
H=I2RT=329.7 joule
R=200×10-6 ohm
T=0.1 sec
I2=329.7/200×10-6×0.1
I=sqrt16.485×106=4.06×103 amp.
6.Calculate the welds per minute work speed and Rpm of circular electrode of 220 mm dia
for caring out seam welding at 4 welds per cm on 1.6 mm thick mild steel tube welding cycle consists of 3 cycle’ on ‘and 2 cycle’ off’ power supply is at 50Hz.Also calculate energy requirement effective resistance between electrodes as 100 micro ohm.
Soln:As per given data
Frequency=50Hz
Cycles for weld=3
Interval cycle=2
Welds required per cm=4
Electrode diameter=220 mm
Welds per minute=Frequency×60/cycles for weld+interval cycles
=50+60/3+2=600 welds/minute
Works speed (mm/min)=welds/min/welds requird/min
=600/4/10=500 mm/min
RPM of electrode=work speed(mm/min)/π×electrode dia
=1500/3.14×220=2.17(rpm)
For 1.6 mm thick M.S plate current requirement is 10,000 amp
Energy requirement=I2Rt=(10000)2×100×10-6×(3/50)
=100×100×3/5=600 joules
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